Combining Recycling with Shared Structure（组合回收性函数和共享结构）
Although you can use recycling functions whenever the arguments to the recycling function won't be used after the function call, it's worth noting that each recycling function is a loaded gun pointed footward: if you accidentally use a recycling function on an argument that is used later, you're liable to lose some toes.
尽管可以在函数实参在函数调用之后不会被使用的情况下使用回收性函数，但值得注意的是，每个回收性函数都是一把指向脚面的装了子弹的枪：如果不小心将一个回收性函数用在了以后会用到的参数上，你肯定会失去一些脚趾。
To make matters worse, shared structure and recycling functions tend to work at cross-purposes. Nondestructive list functions return lists that share structure under the assumption that cons cells are never modified, but recycling functions work by violating that assumption. Or, put another way, sharing structure is based on the premise that you don't care exactly what cons cells make up a list while using recycling functions requires that you know exactly what cons cells are referenced from where.
使事情变得更糟的是，共享结构和回收性函数会用于不同的目的。非破坏性列表函数在点对单元永远不会被修改的假设下返回带有共享结构的列表，但是回收性函数却通过违反这一假设得以正常工作。或者换另一种说法，使用共享结构是基于不在乎究竟由哪些点对单元构成列表这一前提的，而使用回收性函数则要求精确地知道哪些点对单元会在哪里被引用到。
In practice, recycling functions tend to be used in a few idiomatic ways. By far the most common recycling idiom is to build up a list to be returned from a function by "consing" onto the front of a list, usually by PUSHing elements onto a list stored in a local variable and then returning the result of NREVERSEing it.
在实践中，回收性函数会有一些习惯用法。其中最常见的一种是构造一个列表，它是由一个在列表前端不断做点对分配操作的函数返回，通常是将元素 PUSH 进一个保存在局部变量中的列表里，然后返回对其 NREVERSE 的结果。
This is an efficient way to build a list because each PUSH has to create only one cons cell and modify a local variable and the NREVERSE just has to zip down the list reassigning the CDRs. Because the list is created entirely within the function, there's no danger any code outside the function has a reference to any of its cons cells. Here's a function that uses this idiom to build a list of the first n numbers, starting at zero:
这是一种构造列表的有效方式，因为每次 PUSH 都只创建一个点对单元并修改一个局部变量，而 NREVERSE 只需穿过列表并重新赋值每个元素的 CDR。由于列表完全是在函数之内创建，所以完全不存在任何函数之外的代码会引用列表的任何点对单元的风险。下面是一个函数使用该习惯用法来构造一个由从 0 开始的前 n 个数字所组成的列表：
(defun upto (max)
(let ((result nil))
(dotimes (i max)
(push i result))
(nreverse result)))
(upto 10) ==> (0 1 2 3 4 5 6 7 8 9)The next most common recycling idiom is to immediately reassign the value returned by the recycling function back to the place containing the potentially recycled value. For instance, you'll often see expressions like the following, using DELETE, the recycling version of REMOVE:
还有一个最常见的回收性习惯用法， 是将回收性函数的返回值立即重新赋值到含有可能会被回收的值的位置上。例如，你将经常看到像下面这样的表达式，它使用了 DELETE，即 REMOVE 的回收性版本：
(setf foo (delete nil foo))This sets the value of foo to its old value except with all the NILs
removed. However, even this idiom must be used with some care--if foo
shares structure with lists referenced elsewhere, using DELETE instead
of REMOVE can destroy the structure of those other lists. For example,
consider the two lists list-2 and list-3 from earlier that share
their last two cons cells.
这将 foo 的值设置到了它的旧值上，只是所有的 NIL
都被移除了。但即便是这种习惯用法，你在使用时也需小心一些。如果 foo
和在其他位置上引用的列表共享了一些结构，那么使用 DELETE 来代替
REMOVE
可能会破坏其他那些列表的结构。例如早先那两个共享了它们最后两个点对单元的列表
*list-2* 和 *list-3*：
*list-2* ==> (0 4)
*list-3* ==> (1 2 0 4)You can delete 4 from *list-3* like this:
你可以像下面这样将 4 从 *list-3* 中删除：
(setf *list-3* (delete 4 *list-3*)) ==> (1 2 0)However, DELETE will likely perform the necessary deletion by setting
the CDR of the third cons cell to NIL, disconnecting the fourth cons
cell, the one holding the 4, from the list. Because the third cons
cell of *list-3* is also the first cons cell in *list-2*, the
following modifies *list-2* as well:
不过，DELETE 将很可能进行必要的删除，通过将第三个点对单元的
CDR 设置为 NIL，从而从列表中断开了第四个保存了数字
4 的点对单元。由于 *list-3* 的第三个点对单元同时也是 *list-2*
的第一个点对单元，所以上述操作也改变了 *list-2*：
*list-2* ==> (0)If you had used REMOVE instead of DELETE, it would've built a list
containing the values 1, 2, and 0, creating new cons cells as
necessary rather than modifying any of the cons cells in *list-3*. In
that case, *list-2* wouldn't have been affected.
如果使用 REMOVE 来代替 DELETE，它将会构造一个含有值 1、2 和 0
的列表，在必要时创建新的点对单元而不会修改 *list-3*
中的任何点对单元。在这种情况下，*list-2* 将不会受到影响。
The PUSH/NREVERSE and SETF/DELETE idioms probably account for 80 percent of the uses of recycling functions. Other uses are possible but require keeping careful track of which functions return shared structure and which do not.
PUSH/NREVERSE 和 SETF/DELETE 的习惯用法很可能占据了 80% 的回收性函数使用。其他的使用是可能的，但需要小心地跟踪哪些函数返回共享的结构而哪些没有。
In general, when manipulating lists, it's best to write your own code in a functional style--your functions should depend only on the contents of their list arguments and shouldn't modify them. Following that rule will, of course, rule out using any destructive functions, recycling or otherwise. Once you have your code working, if profiling shows you need to optimize, you can replace nondestructive list operations with their recycling counterparts but only if you're certain the argument lists aren't referenced from anywhere else.
总之，当操作列表时，最好是以函数式风格来编写自己的代码——函数应当只依赖于它们的列表实参的内容而不应该修改它们。当然，按照这样的规则将会排除对任何破坏性函数的使用，无论是回收性的还是其他。一旦运行了代码，如果性能评估显示需要进行优化，你可以将非破坏性列表操作替换成相应的回收性操作，但只有当你确定其他任何位置不会引用实参列表时才可以这样做。
One last gotcha to watch out for is that the sorting functions SORT, STABLE-SORT, and MERGE mentioned in Chapter 11 are also recycling functions when applied to lists. However, these functions don't have nondestructive counterparts, so if you need to sort a list without destroying it, you need to pass the sorting function a copy made with COPY-LIST. In either case you need to be sure to save the result of the sorting function because the original argument is likely to be in tatters. For instance:
最后需要注意的是，当第 11 章里提到的排序函数 SORT、STABLE-SORT 和 MERGE 当应用于列表时，它们也是回收性函数。 不过，这些函数却并没有非破坏性的同伴，因此当需要对列表排序而又不破坏它时，你需要传给排序函数一个由 COPY-LIST 生成的列表副本。无论哪种情况，你都需要确保可以保存排序函数的结果，因为原先的实参很可能已经一团糟了。例如：
CL-USER> (defparameter *list* (list 4 3 2 1))
*LIST*
CL-USER> (sort *list* #'<)
(1 2 3 4) ; looks good
CL-USER> *list*
(4) ; whoops!